ACCELERATION DUE TO GRAVITY OF THE EARTH

NEWTONS LAW OF GRAVITATION |ACCELERATION DUE TO GRAVITY AT THE SURFACE OF EARTH AND ABOVE IT

If g is the acceleration due to gravity on the earth's surface the gain in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R to earth is (NmgR)/(2) Find the value of N .

The acceleration due to gravity on the earth of radius R_(e) is g_(e) and that on moon of radius R_(m) is g_(m) . The ratio of the masses of the earth and moon is given by

A capillary tube is taken from the Earth to the surface of the moon. The rise of the liquid column on the Moon (acceleration due to gravity on the Earth is 6 times that of the Moon) is

A ball is launched from the top of Mt. Everest which is at elevation of 9000 m. The ball moves in circular orbit around earth. Acceleration due to gravity near the earth's surface is g. The magnitude of the ball's acceleration while in orbit is -

The acceleration due to gravity on the Earth's surface is about 6 times that on the Moon. The radius of the Moon is nearly (4)/(18) times that of the Earth. The ratio of the binding energy of a body at rest on the Earth's surface to that on the Moon's surface is about

A body of mass m rises to a height h=R//5 from the earth's surface where R is earth's radius. If g is acceleration due to gravity at the earth's surface, the increase in potential energy is

What will be the acceleration due to gravity at height h if h gt gt R . Where R is radius of earth and g is acceleration due to gravity on the surface of earth

Calculate the value of acceleration due to gravity at a place of lititude 30^(@) . Radius of the Earth 6.4xx 10^(6)m .The value of acceleration due to gravity on Earth is 9.8 m//s^(2) .