Ch. 3 & 4 VVI Question

Class 9th English VVI Questions?| Set 1 | 9th English Complete Book Most Important Questions

Note : Consider structures I to VII and answer the questions 23 - 26. I. CH_3 - CH_2 - CH_2 - CH_2 - OH II. CH_3 - CH_2 - underset(underset(OH)|) CH - CH_3 III. CH_3 - underset(underset(OH)|) overset(overset(CH_3)|)C- CH_3 IV. CH_3 - underset(underset(CH_3)|) CH - CH_3 - OH V. CH_3 - CH_2 - O - CH_2 - CH_3 VI. CH_3 - O - CH_2 - CH_2 - CH_2 - CH_3 VII. CH_3 - O - underset(underset(CH_3)|) CH - CH_3 Which of the above compounds form pairs of metamers ?

Note : Consider structures I to VII and answer the questions 23 - 26. I. CH_3 - CH_2 - CH_2 - CH_2 - OH II. CH_3 - CH_2 - underset(underset(OH)|) CH - CH_3 III. CH_3 - underset(underset(OH)|) overset(overset(CH_3)|)C- CH_3 IV. CH_3 - underset(underset(CH_3)|) CH - CH_3 - OH V. CH_3 - CH_2 - O - CH_2 - CH_3 VI. CH_3 - O - CH_2 - CH_2 - CH_2 - CH_3 VII. CH_3 - O - underset(underset(CH_3)|) CH - CH_3 Identify the pairs of compounds that represent chain isomerism.

Note : Consider structures I to VII and answer the questions 23 - 26. I. CH_3 - CH_2 - CH_2 - CH_2 - OH II. CH_3 - CH_2 - underset(underset(OH)|) CH - CH_3 III. CH_3 - underset(underset(OH)|) overset(overset(CH_3)|)C- CH_3 IV. CH_3 - underset(underset(CH_3)|) CH - CH_3 - OH V. CH_3 - CH_2 - O - CH_2 - CH_3 VI. CH_3 - O - CH_2 - CH_2 - CH_2 - CH_3 VII. CH_3 - O - underset(underset(CH_3)|) CH - CH_3 Identify the pairs of compounds which are functional group isomers.

Note : Consider structures I to VII and answer the questions 23 - 26. I. CH_3 - CH_2 - CH_2 - CH_2 - OH II. CH_3 - CH_2 - underset(underset(OH)|) CH - CH_3 III. CH_3 - underset(underset(OH)|) overset(overset(CH_3)|)C- CH_3 IV. CH_3 - underset(underset(CH_3)|) CH - CH_3 - OH V. CH_3 - CH_2 - O - CH_2 - CH_3 VI. CH_3 - O - CH_2 - CH_2 - CH_2 - CH_3 VII. CH_3 - O - underset(underset(CH_3)|) CH - CH_3 Identify the pairs of compounds that represent position isomerism.

2-methyl-2-butene will be represented as (1) CH_(3)-oversetoverset(CH_(3))(|)CH-CH_(2)CH_(3) (2) CH_(3)-undersetunderset(CH_(3))(|)C=CH-CH_(3) (3) CH_(3) - CH_(2) - undersetunderset(CH_(3))(|)C=CH_(2) (4) CH_(3)-undersetunderset(CH_(3))(|)CH-CH = CH_(2)