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10TH KE BAAD KYA KAREN??|STREAM SELECTIO...

10TH KE BAAD KYA KAREN??|STREAM SELECTION

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Refer to illustration 5.10 , the energy released by the alpha - decay of ._(92)^(238) U is found to be 4.3 MeV . Since this energy is carried away as kinetic energy of the recoiling ._(90)^(234)Th . nucleus and the alpha - particles, it follows that KE_(Th) +KE_(alpha )=4.3 MeV . However, KE_Th and KE_alpha are not equal. Which particle carries away more kinetic energy, the overset(234)(90)Th nucleus or the alpha - particle? .

Given KE=(1)/(2)mv^(2) . If m=10kg, v=5m//s then find the value of KE?

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