Find all integers `a`,`b`,`c` such that
`a^2=bc+1`
`b^2=ca+1`

If ab + bc + ca = 0 , then the value of 1/(a^2 - bc) + 1/(b^2 - ca) + 1/(c^2 - ab) will be :

If a , b , c are all non-zero and a+b+c=0 , then (a^(2))/(bc)+(b^(2))/(ca)+(c^(2))/(ab)= ? .

Without expanding determinant at any stage evaluate |(1,1,1),(a,b,c),(a^(2)-bc,b^(2)-ca,c^(2)-ab)|

The value of the determinant |{:(1,a, a^(2)-bc),(1, b, b^(2)-ca),(1, c, c^(2)-ab):}| is…..

Find the area of triangle formed by the points (a+b+c,a+b+c), ((ab+bc+ca+c^(2))/c,(ab+bc+ca+a^(2))/a) "and" ((ab+bc+ca+a^(2))/c,(ab+bc+ca+b^(2))/a)