A capacitor is charged by connecting a battery across its plates. It stores energy U. Now the battery is disconnected and another identical capacior is connected across it, then the energy stores by both capacitors of the system will be

A capacitor is charged by connecting a battery across its plates. It stores energy U. now the battery is disconnected and another identical capacitor is connected across it. What will be the energy stored by both capacitors of the system?

A capacitor is charged by connecting a battery. It stores energy U. Now the battery is disconnected and another identical capacitor is connected across it. Then the energy stored by both capacitor of the combination will be

A capacitor is chared to store an energy U . The charging battery is disconnected. An Identical capacitor is now connected to the first capacitor in parallel. The energy in each capacitor is now.

A capacitor is charged with a battery and energy stored is U. After disconnecting battery another capacitor of same capacity is connected in parallel with it. Then energy stored in each capacitor is:

A capacitor is charged with a battery and energy stored is U. After disconnecting battery another capacitor of same capacity is connected in parallel with it. Then energy stored in each capacitor is:

A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel.The total electrostatic energy of resulting system

A capacitor is charged until its stored energy is 3J and then the charging battery is removed. Now another uncharged capacitor is connected across it and it is found that charge is distributed equally in the two capacitors. The final value of total energy stored in the electric fields is :