MOTIONAL EMF

A copper rod of length L is moving at a uniform speed v parallel to along straight wire carrying a current of I as shown in figure-5.25. The rod is perpendicular to the wire with its ends at distance a and b from if . Calculate the motional EMF induced in the rod.

Question based on Motional Electro motive force (emf)

A conducting disc of radius r rotaes with a small but constant angular velocity omega about its axis. A uniform magnetic field B exists parallel to the axis of rotation. Find the motional emf between the centre and the periphery of the disc.

With the help of a neatly drawn labelled diagram, prove that the magnitude of motional emf .e. is given by e=Blv, where .I. is the length of a metallic rod and v is the velocity with which it is pulled in a transverse magnetic field .B..

A conducting disc of radius r rotaes with a small but constant angular velocity omega about its axis. A uniform magnetic field B exists parallel to the axis of rotation. Find the motional emf between the centre and the periphery of the disc.

A conducting disc of radius r rotaes with a small but constant angular velocity omega about its axis. A uniform magnetic field B exists parallel to the axis of rotation. Find the motional emf between the centre and the periphery of the disc.

A metal rod is falling toward the surface of the Earth near the equator. As it falls, one end of the rod become positively charged due to the motional emf of the rod through the Earth's magnetic field. The rod is oriented so that

Assertion : Motional induced emf e = Bvl can be derived from the relation e = -(dtheta)/(dt) Reason : Lenz's law is a consequence of law of conservation of energy.

A rod of length L rotates in the form of a conical pendulum with an Angular velocity omega about its axis as shown in Fig. 3.165. The rod makes an angle theta with the axis. The magnitude of the motional emf developed across the two emf of the rod is