The equation of the tangent from the point (0, 1) to the circle `x^2+y^2-2x-6y+6=0`

Solve the following:Find theequations of the tangents from the point A(3,2) to the circle x^2+y^2+4x+6y+8=0

Find the equations of the tangents from the point A(3,2) to the circle x^(2)+y^(2)+4x+6y+8=0 .

Find the equations of the tangents from the point A(3,2) to the circle x^(2)+y^(2)+4x+6y+8=0 .

Find the equations of the tangents drawn from the point A(3, 2) to the circle x^2 + y^2 + 4x + 6y + 8 = 0

The lngth of the tangent from the point (1, 1) to the circle x^2 + y^2 + 4x + 6y + 1 = 0 is

The length of the chord of contact of the tangents drawn from the point (-2,3) to the circle x^2+y^2-4x-6y+12=0 is:

The length of the chord of contact of the tangents drawn from the point (-2,3) to the circle x^2+y^2-4x-6y+12=0 is:

Length of the tangent. Prove that the length t o f the tangent from the point P (x_(1), y(1)) to the circle x^(2) div y^(2) div 2gx div 2fy div c = 0 is given by t=sqrt(x_(1)^(2)+y_(1)^(2)+2gx_(1)+2fy_(1)+c) Hence, find the length of the tangent (i) to the circle x^(2) + y^(2) -2x-3y-1 = 0 from the origin, (2,5) (ii) to the circle x^(2)+y^(2)-6x+18y+4=-0 from the origin (iii) to the circle 3x^(2) + 3y^(2)- 7x - 6y = 12 from the point (6, -7) (iv) to the circle x^(2) + y^(2) - 4 y - 5 = 0 from the point (4, 5).