The atomic masses of the hydrogen isotopes are
Hydrogen `m_1H^1=1.007825` amu
Deuterium `m_1H^2=2.014102` amu
Tritium `m_1H^3=3.016049` amu
The number of fusion reactions required to generate 1kWh is nearly

The atomic masses of the hydrogen isotopes are Hydrogen m_1H^1=1.007825 amu Deuterium m_1H^2=2.014102 amu Tritium m_1H^3=3.016049 amu The mass of deuterium, _1H^2 that would be needed to generate 1 kWh

The atomic masses of the hydrogen isotopes are Hydrogen m_1H^1=1.007825 amu Deuterium m_1H^2=2.014102 amu Tritium m_1H^3=3.016049 amu The mass of deuterium, _1H^2 that would be needed to generate 1 kWh. (energy released by 1 fusion is 4MeV)

The atomic masses of the hydrogen isotopes are Hydrogen m_1H^1=1.007825 amu Deuterium m_1H^2=2.014102 amu Tritium m_1H^3=3.016049 amu The energy released in the reaction, _1H^2+_1H^2rarr_1H^3+_1H^1 is nearly

The atomic masses of the hydrogen isotopes are Hydrogen m_1H^1=1.007825 amu Deuterium m_1H^2=2.014102 amu Tritium m_1H^3=3.016049 amu The energy released in the reaction, _1H^2+_1H^2rarr_1H^3+_1H^1 is nearly

The correct order of wavelength of Hydrogen (._(1)H^(1)) , Deuterium (._(1)H^(2)) and Tritium (._(1)H^(3)) moving with same kinetic energy is

The correct order of wavelength of Hydrogen (._(1)H^(1)) , Deuterium (._(1)H^(2)) and Tritium (._(1)H^(3)) moving with same kinetic energy is

The atomic mass of oxygen is 16.000 amu. m_("electron")=0.00055" amu ",m_("proton")=1.007593" amu "m_("neutron")=1.008982 amu. The binding energy per nucleon is ______ MeV (nearly)

Calculate the binding energy of a deutron. Given that mass of proton = 1.007825 amu mass of neutron = 1.008665 amu mass of deutron = 2.014103 amu

The atomic masses of Li, He and proton are 7.01823 amu, 4.00387 amu and 1.00715 amu respectively. Calculate the energy evolved in the reaction, 3^(Li^(7)) + 1^(H^(1)) rarr 2 2^(He^(4)) + triangle E Given 1 amu = 931 MeV.