A force of 5 N, making an angle `theta` with the horizontal, actig on an object displaces it by 0.4 m along the horizontal direction. If the object gains kinetic energy of 1J. The horizontal component of the force is

A force of 5 N, making an angle 0 with the horizontal, acting on an object displaces it by 0.4 m along the horizontal direction. If the object gains kinetic energy of 1 J, the horizontal component of the force is

A force of 5 N making an angle with the horizontal acting on an object displaces it by 0.4 m along the horizontal direction. If the object gains kinetic energy of 1 J the horizontal component of the force is

A force of 5 N making an angle with the horizontal acting on an object displaces it by 0.4 m along the horizontal direction. If the object gains kinetic energy of 1 J, the horizontal component of the force is :

A force of 4 N is acting at an angle of 30^(@) to the horizontal. Find its component along axeses.

Pravin has applied a force of 100 N on an object, at an angle of 60^@ to the horizontal. The object gets displaced in the horizontal direction and 400 J work is done. What is the disptacement of the object? (cos 60^@ =1/2)

A force of 10 N acting on a body at an angle of 30^(@) with the horizontal direction displaces it horizontally through a distance of 6 m. Calculate the work done.

Pravin has applied a force of 100 N on an object, at an angle of 60° to the horizontal. The object gets displaced in the horizontal direction and 400 J work is done. What is the displacement of the object?

A force acts on a body at a certain angle with the horizontal such that the vertical component is twice the horizontal component . What is the inclination of the force ?