If `I_(0)` is the threshold wavelength for photoelectric emission, 1 the wavelength of light falling on the surface of a metal and m is the mass of the electron, then the velocity of ejected electron is given by

If lambda_(0) is the threshold wavelength for photoelectric emission. lambda wavelength of light falling on the surface on the surface of metal, and m mass of electron. Then de Broglie wavelength of emitted electron is :-

If lambda_(0) is the threshold wavelength for photoelectric emission. lambda wavelength of light falling on the surface on the surface of metal, and m mass of electron. Then de Broglie wavelength of emitted electron is :-

In photoelectric emission, the velocity of electrons ejected from near the surface is

In photoelectric emission, the velocity of electrons ejected from near the surface is

The threshold wavelength for photoelectric emission in tungsten is 2300 Å. What wavelength of light must be used to eject electrons with a maximum energy of 1.5 eV?

Assertion : In photoelectron emission the velocity of electron ejected from near the surface is larger than that coming from interior of metal. Reaon : The velocity of ejected electron will be zero.

If lambda_(0) is the threshold wavelnegth of a metal and lambda is the wavelength of the incident radiation, the maximum velocity of the ejected electron from the metal would be