Sum the series `tan^-1 (x/(1+1*2x^1))+tan^-1 (x/(1+2*3x^2))+…+tan^-1 (x/(1+n*(n+1)x^2))`

Sum the series tan^-1 (x/(1+1*2x^2))+tan^-1 (x/(1+2*3x^2))+…+tan^-1 (x/(1+n*(n+1)x^2))

Find the sum tan^-1 (x/ (1+1.2x^2))+tan^-1 (x/(1+2.3x^2))+…+tan^-1 (x/(1+n(n+1)x^2)) xgt0

Find the sum tan^-1 (x/ (1+1.2x^2))+tan^-1 (x/(1+2.3x^2))+…+tan^-1 (x/(1+n(n+1)x^2)) xgt0

Using the principle of mathematical induction to show that tan^(−1)(x/(1+1.2.x^2))+tan^(−1)(x/(1+2.3.x^2))+.....+tan^(−1)(x/(1+n(n+1)x^2)) = tan^(-1)(n+1)x-tan^(-1)x , forall x in N .

For all n in N, x in R, tan^(-1) [ ( x)/( 1.2+ x^2) ] + tan^(-1) [ (x)/( 2.3+ x^2) ] + …. + tan^(-1) [ ( x)/( n(n+1) +x^2) ] =

[ If xgt0 then which of the following is true 1) tan^(-1)xgt(x)/(1+x^(2)), 2) tan^(-1)x=(x)/(1+x^(2)) 3) tan^(-1)xlt(x)/(1+x^(2)), 4) tan^(-1)x!=(x)/(1+x^(2))]

Find the sum of each of the following series :(i) tan^-1(1/(x^2+x+1))+tan^-1 (1/(x^2+3x+3))+tan^-1(1/(x^2+5X+7))+tan^-1(1/x^2+7x+13)) ......upto n.

Find the sum of each of the following series :(i) tan^-1(1/(x^2+x+1))+tan^-1 (1/(x^2+3x+3))+tan^-1(1/(x^2+5X+7))+tan^-1(1/x^2+7x+13)) ......upto n.

Find the sum of each of the following series :(i) tan^-1(1/(x^2+x+1))+tan^-1 (1/(x^2+3x+3))+tan^-1(1/(x^2+5X+7))+tan^-1(1/x^2+7x+13)) ......upto n.

AA n in N,x in R,tan^(-1)[(x)/(1.2+x^(2))]+tan^(-1)[(x)/(2.3+x^(2))]+......+tan^(-1)[(x)/(n(n+1)+x^(2))]=