`int_- 1^(1//2)|xcos(pix)|\ dx`

Evaluate: int_-1^(3/2) |xsin(pix)|dx

The value of int_(-1//2)^(1//2) |xcos((pix)/(2))|dx is

The value of int_(-1//2)^(1//2) |xcos((pix)/(2))|dx is

Evaluate int_(-1)^((3)/(2))|xsin(pix)|dx

Evaluate : int_(-1)^(3/(2))|x"sin"(pix)|dx

Evaluate: underset(-1)overset(1//2) int|x cos (pix)| dx

(i) Show that int_(0)^(pi)xf(sinx)dx =(pi)/(2)int_(0)^(pi)f (sin x)dx. (ii) Find the value of int_(-1)^(3//2)|x sin pix|dx .

int_(0)^(2)|cos""(pix)/(2)|dx=