`sintheta+costheta=sqrt2` then `sin^(16)theta` is (A) `cos^16theta/2^10` (B) `sec^16theta/2^8` (C) `1/(2sec^16theta)` (D) `1/(2^16cos^16theta)`

sin theta+cos theta=sqrt(2) then sin^(16)theta=

sin theta + cos theta =sqrt(2), then sin^(16)theta =______

16sin theta-12sin^(2)theta?

If sin theta+ cos theta= (1)/(2) , then 16(sin (2theta)+ cos (4theta) + sin (6theta)) is equal to

2costheta - cos5theta = 16sin^(2)theta cos^(3)theta

If sintheta+costheta=1/2 then find the value of 16(sin2theta+cos4theta+sin6theta)

8 sin theta * cos theta * cos 2 theta * cos 4 theta = A) sin 4 theta B) sin 8 theta C) sin 16 theta D) cos 8 theta

If sec theta (cos theta + sin theta) = sqrt2 , then what is the value of (2 sin theta)//(cos theta- sin theta) ? यदि sec theta (cos theta + sin theta) = sqrt2 है,तो (2 sin theta)//(cos theta- sin theta) का मान क्या है?

tan theta + 2 tan 2 theta + 4 tan 4theta + 8 tan 8 theta + 16 tan 16 theta + 32 cot 32 theta =