If `x = cos theta - cos 2theta, y = sin theta - sin 2theta,` then `dy/dx` is

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta . then find dy/dx

If x = 2 cos theta - cos 2 theta, y = 2 sin theta - sin 2 theta, find dy/dx at theta = pi/2

if x = "cos" theta - "cos" 2 theta, y = "sin" theta - "sin" 2 theta , then dy/dx is

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

If x=2cos theta -cos 2theta ,y=2sin theta -sin 2theta ,then (dy)/(dx) =

If x = 3 cos theta - 2 cos^3 theta,y = 3 sin theta - 2 sin^3 theta , then dy/dx is

If x = 2 cos theta - cos 2theta and y = 2 sin theta - sin 2theta then prove that : (dy)/(dx)=tan (3 theta)/(2)

If x = sin theta - cos theta and y = sin theta + cos theta , then (dy)/(dx) =