For what value of `k` is the circle `x^2 + y^2 + 5x + 3y + 7 = 0` and `x^2 + y^2 - 8x + 6y + k = 0` cut each other orthogonally.

The value of k for which the circles x^2 - y^2 + 3x - 7y +k = 0 and x^2 + y^2 - 4x + 2y - 14 = 0 would intersect orthogonallys

For the circles x^2 + y^2 - 2x + 3y + k = 0 and x^2 + y^2 + 8x - 6y - 7 = 0 to cut each other orthogonally the value of k must be

For the circles x^(2) + y^(2) - 2x + 3y + k = 0 and x^(2) + y^(2) + 8x - 6y - 7 = 0 to cut each other orthogonally the value of k must be

If x^(2) + y^(2) - 2x + 3y + k = 0 " and " x^(2) + y^(2) + 8x - 6y = 7 = 0 cut each other orthogonally , the value of k must be

Show that the circles x^2 + y^2 - 2x-6y-12=0 and x^2 + y^2 + 6x+4y-6=0 cut each other orthogonally.

Show that the circles x^2 + y^2 - 2x-6y-12=0 and x^2 + y^2 + 6x+4y-6=0 cut each other orthogonally.

If the circles x^(2) + y^(2) - 6x - 8y + 12 = 0 , x^(2) + y^(2) - 4x + 6y + k = 0 cut orthogonally, then k =

If the two circle x^(2) + y^(2) - 10 x - 14y + k = 0 and x^(2) + y^(2) - 4x - 6y + 4 = 0 are orthogonal , find k.

The value of k, if the circles 2x ^(2) + 2y ^(2) - 4x + 6y = 3 and x ^(2) + y ^(2) + kx + y =0 cut orthogonally is