The argument of `1-costheta - isin theta` is

The argument of (1-sin theta)+i cos theta is

The mod -amplitude form of 1+cos theta-isin theta is

Write the Argument of (1+sqrt3i)(costheta+isintheta)

(1)/(cos theta-isin theta) Find modulus

If theta is real then the modulus of (1)/(1 + cos theta + isin theta) is

The general value of theta which satisfies the equation (cos theta + isin theta) (cos 3theta+ isin3theta)…[cos(2n-1)theta+isin(2n-1)theta]=1 is

If (1 + cos theta - isin theta) ( 1+ cos 2 theta + isin 2 theta) = x +iy then x^(2) + y^(2) =

If theta= (pi)/(6) , then the 10th term of the series 1+(cos theta +isin theta)+(cos theta +isin theta)^(2)+"……." is

If z = 1 -cos theta+ isin theta then |z| is equal to

The general value of theta which satisfies the equation (costheta+isintheta) (cos3theta+isin3theta)...[(cos(2r-1)theta+isin(2r-1)theta)]=1 is