A weak base MOH was titrated against a strong acid. The `pH` at `1/4` the equivalence point was 9.3. What will be the `pH` at `3/4` th equivalence point in the same titration? `(log3=0.48)`

A weak base MOH was titrated against a strong acid. The pH at 1/4 th equivalence point was 9.3. What will be the pH at 3/4 th equivalence point in the same titration? (log3=0.48)

A weak base BOH was titrated against a strong acid. The pH at 1/4 the equivalence point was 9.24. Enough strong base was now added (6m eq.) to completely convert the salt. The total volume was 50 ml. Find the pH at this point.

A weak base BOH was titrated against a strong acid. The pH at 1/4 the equivalence point was 9.24. Enough strong base was now added (6m eq.) to completely convert the salt. The total volume was 50 ml. Find the pH at this point.

Why the pH at the equivalence point of a titration may differ from 7 ?

A strong acid is titrated with weak base. At equivalence point, pH will be :

A strong acid is titrated with weak base. At equivalence point, pH will be :

A weak base (BOH) with K_(b) = 10^(-5) is titrated with a strong acid (HCl) , At 3//4 th of the equivalence point, pH of the solution is:

A weak base (BOH) with K_(b) = 10^(-5) is titrated with a strong acid (HCl) , At 3//4 th of the equivalence point, pH of the solution is: