`30 kg` ice at `0^@C` and `20 g` of steam at `100^@C` are mixed. The composition of the resultant mixture is

5 g of ice at 0^@C and 20 g of water at 45^@C are mixed. The temperature of the mixture will be

1g of ice at 0^@ C is mixed 1 g of steam at 100^@ C . The mass of water formed is

1 g of steam at 100^@C and an equal mass of ice at 0^@C are mixed. The temperature of the mixture in steady state will be (latent heat of steam =540 cal//g , latent heat of ice =80 cal//g ,specific heat of water =1 cal//g^@C )

1 g of steam at 100^@C and an equal mass of ice at 0^@C are mixed. The temperature of the mixture in steady state will be (latent heat of steam =540 cal//g , latent heat of ice =80 cal//g ,specific heat of water =1 cal//g^@C )

10 g of ice at 0^@C is mixed with 100 g of water at 50^@C . What is the resultant temperature of mixture

60 g of ice at 0^(@)C is mixed with 60 g of steam at 100^(@)C . At thermal equilibrium, the mixture contains

2g ice at 0^(@)C is mixed with 1 g steam at 100^(@)C . Find the final temperature of the mixture.

2g ice at 0^(@)C is mixed with 1 g steam at 100^(@)C . Find the final temperature of the mixture.