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The ratio of mass percent of C and H of ...

The ratio of mass percent of C and H of an organic compound `(C_(X)H_(Y)O_(Z))` is 6 : 1. If one molecule of the above compound `(C_(X)H_(Y)O_(Z))` contains half as much oxygen as required to burn one molecule of compound `C_(X)H_(Y)` completely to `CO_(2)` and `H_(2)O`. The empirical formula of compound `C_(X)H_(Y)O_(Z)` is

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The ration of mass per cent of C and H of an organic compound (C_(x)H_(y)O_(z)) "is"6:1 . If one molecule of the above compound (C_(x)H_(Y)O_(z)) contains half as much oxygen as required to burn one molecule of compound C_(x)H_(Y) compleltely to CO_(2) and H_(2)O . The empirial formula of compound C_(x)H_(y)O_(z) is:

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