Prove that: `(cos6theta+6cos4theta+15 cos2theta+10)/(cos5theta+5cos3theta+10 costheta)=2costheta`

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Prove that: (cos6 theta+6cos4 theta+15cos2 theta+10)/(cos5 theta+5cos3 theta+10cos theta)=2cos theta

(cos6 theta+6cos4 theta+15cos2 theta+10)/(cos5 theta+5cos3 theta+10cos theta)

The value of (cos6theta+6cos4theta+15cos2theta+10)/(cos5theta+5cos3theta+10costheta) is :

( cos 6 theta +6 cos 4 theta + 15 cos 2 theta + 10)/( cos 5 theta + 5 cos 3 theta + 10 cos theta)=

4costheta cos 2theta cos3theta - 2cos 4theta=1

Find the value of (cos6 theta+6cos4 theta+15cos2 theta+10)/(cos5 theta+5cos theta+10cos theta)

costheta.cos2theta.cos3theta=1/4

Prove that cos5theta=16cos^(5)theta-20cos^(3)theta+5costheta .