A balloon is going up with a uniform speed 20 m/s. It was at a height of 100 m from ground, when a stone is dropped from its basket. Find the time taken by the stone to reach the groimd and the height of the balloon from the ground, when stone hits the ground. (Take `g = 10 m//s^(2)`)

A balloon rises with uniform velocity of 10 ms^(-1) . When the balloon is at a height of 75 m if a stone is dropped from it the time taken by it to reach the ground is

A balloon rises with uniform velocity of 10 ms^(-1) . When the balloon is at a height of 75 m if a stone is dropped from it the time taken by it to reach the ground is

A balloon is going vertically upwards with a velocity of 10 m//s . When it is 75 m above the ground, a stone is gently relesed from it. The time taken by the stone to reach the ground is (g=10 m//s^(2))

A balloon starts rising from the ground with an acceleration 2 ms^(-2) . After 5 second , a stone is released from the ballooon. Find the time taken by the stone to reach the ground after its release and total height attained by ballooon when stone reaches the ground. Take g==10 ms^(-2) .

A stone is dropped from a stationary hot air balloon in the air travels 14.7m in the last second before it hits the ground. Find the height of the balloon from the ground.

A balloon is going vertically upward with a velocity of 15 ms^-1 . When it is at a height of 50 m above the ground a stone is gently dropped from it. The stone will reach the ground in time (take g = 10 ms^-2) :

A balloon was moving upwards with a uniform velocity of 10 m/s. An object of finite mass is dropped from the balloon when it was at a height of 75 m from the ground level. The height of the balloon from the ground when object strikes the ground was around : (takes the value of gas 10 m//s^2)

A balloon starts rising from the ground with a constant acceleration of 1.25 m/ s^2 . After 8s, a stone is released from the balloon. Find the time taken by the stone to reach the ground. (Assume, g = 10m/ s^2 )