A spherical charged conductor has `sigma` as the surface density of charge. The electric field on its surface is E. If the radius of the sphere is doubled keeping the surface density of charge unchanged, what will be the electric field on the surface of the new sphere -

A spherical charged conductor has sigma as the surface charge density. The electricfield on its surface is E. The radius of the sphere is doubled keeping the surface charge density unchanged. Then the electric field on the surface of the new sphere is,

A spherical charged conductor has surface density of charge as sigma . The electric field intensity on its surface is E . If the radius of the surface is doubled, keeping sigma uncharged, what will be the electric field intensity on the new sphere ?

A spherical charged conductor has surface density of charge as sigma . The electric field intensity on its surface is E . If the radius of the surface is doubled, keeping sigma uncharged, what will be the electric field intensity on the new sphere ?

The surface density on a copper sphere is sigma . The electric field strength on the surface of the sphere is

The surface density on a copper sphere is sigma . The electric field strength on the surface of the sphere is

The surface density on the copper sphere is 'sigma'. The electric field strength on the surface of the sphere is :

A spherical charged conductor has surface charge density sigma .The intensity of electric field and potential on its surface are E and V .Now radius of sphere is halved keeping the charge density as constant .The new electric field on the surface and potneial at the centre of the sphere are

A spherical charged conductor has surface charge density sigma .The intensity of electric field and potential on its surface are E and V .Now radius of sphere is halved keeping the charge density as constant .The new electric field on the surface and potential at the centre of the sphere are

A spherical charged conductor has surface charge density σ.The intensity of electric field and potential on its surface are E and V, now radius is halved keeping surface charge density to be constant. Then the new values will be