Let `[in_(0)]` denote the dimensional formula of the permittivity of vacuum. If M= mass, L=length, T=Time and A= electric current, then:

Let [in_(0)] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = elctric current , then :

Let [epsi_(0)] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T= time and A= electric current, then

Let [epsilon_(0)] denote the dimensional formula of the permittivity of vacuum. If M =mass, L =length, T =time and A = electric current, then :

Let |epsi_(0)| denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then

Let [epsilon_0] denote the dimensional formula of the permittivity of vacuum. If M= j mass, L=length, T=time and A= electric j current, then [epsilon_0] =_________.

Let in_0 denote the dimensional formula of the permittivity of vaccum. If M = mass, L l= length , T = time and A = electric current, then

Let epsi_0 denote the dimensional formula of the permittivity of vacuum. If M= mass , L=length , T=time and A=electric current , then dimension of permittivity is given as [M^(p)L^(q)T^(r)A^(s)] . Find the value of (p-q+r)/(s)

Let epsi_0 denote the dimensional formula of the permittivity of vacuum. If M= mass , L=length , T=time and A=electric current , then dimension of permittivity is given as [M^(p)L^(q)T^(r)A^(s)] . Find the value of (p-q+r)/(s)

Let [varepsilon_0] denote the dimensional formula of the permittivity of vacuum. If M =mass , L=length, T=time and I= electric current Then