Find the coordinates of a point on the parabola `y=x^2+7x+2` which is closest to the straight line `y=3x-3.`

Find the co-ordinates of a point on the parabola y=x^(2)+7x+2 which is closed to the straight line y=3x-3 .

Find the coordinates of a point of a parabola y=x^(^^)2+7x+2 which is closest to the straight line y=3x-3

The co-ordinates of the point on the parabola y=(x^(2)+10x+3) which is nearest to the straight line y=4x-7 are

The point on the parabola y = x^(2) + 7x + 2 which is elosest to the line y = 3x - 3 is

Using calculus find the coordinates of the point on the parabola y=x^(2) , which is at the least distance from the straight line y=2x-4 .

If P is a point on the parabola y = x^2+ 4 which is closest to the straight line y = 4x – 1, then the co-ordinates of P are :

Find the equation of the tangent to the parabola y^(2)=4x+5 which is parallel to the straight line y=2x+7

The points on y=x^2+7x+2 which is closest to the line y=3x-3 is