If `y=e^(-x)(A cos x + B sin x)` then y is a situation of

If y=e^(-x)(A cos x + B sin x) then y is a solution of

If y = e^(2x)(A cos 3x - B sin 3x) , then y satisfies

The differential equation of the family of curves y=e^(x)(A cos x+B sin x), where A and B are arbitrary constants is

If y =a cos (sin x) + b sin (sin x) then y _(2) + (tan x) y_(1)=

In y = e^(x) ( a cos x + b sin x) form the differential equation by eliminating arbitrary constants a and b .

If y = tan^(-1) ((a cos x - b sin x)/(b cos x + a sin x)) " then " (dy)/(dx) = ?

If y=e^(x)(sin x +cos x) , then find dy/dx .

Find the differential equation from y = e^x (A cos x + B sin x) , where A and B are arbitrary constants.