Let `y= (x)` be the solution of the differential equation `(dy)/(dx) + 2y = (x) ` .Where `:f (x) = {1, x in [0,1] and 0,` otherwise If `y(0)=0` then `y(3/2)` is

Let Y = y(x) be the solution of the differential equation ( dy ) /( dx) + 2y = f(x) , where f(x) = { {:(1, x in [0,1]),( 0, " Otherwise "):} IF y(0) =0 then y ((3)/(2)) is :

Let Y = y(x) be the solution of the differential equation ( dy ) /( dx) + 2y = f(x) , where f(x) = { {:(1, x in [0,1]),( 0, " Otherwise "):} IF y(0) =0 then y ((3)/(2)) is :

The solution of the differential equation x(dy)/(dx) + 2y = x^2 (X ne 0) with y(1) =1, is :

The solution of the differential equation x(dy)/(dx) + 2y = x^2 (X ne 0) with y(1) =1, is :

Solution of the differential equation (dy)/(dx)+(2y)/(x)=0 , where y(1)=1 , is

Solution of the differential equation (dy)/(dx)+(2y)/(x)=0 , where y(1)=1 , is

The solution of the differential equation x(dy)/(dx) = 2y + x^(3)e^(x), where y = 0 when x = 1 is

The solution of the differential equation x(dy)/(dx) = 2y + x^(3)e^(x), where y = 0 when x = 1 is