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If sin A = nsin B, then (n-1)/(n+1) tan(...

If sin A = nsin B, then `(n-1)/(n+1) tan((A+B)/2)` is equal to

Answer

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Knowledge Check

  • If sin A=n sin B, then (n-1)/(n+1)"tan" (A+B)/2 is equal to

    A
    `"sin"(A-B)/2`
    B
    `"tan"(A-B)/2`
    C
    `"cot"(A-B)/2`
    D
    none of these

  • If sin A=n sin B, then (n-1)/(n+1)"tan" (A+B)/2 is equal to

    A
    `"sin"(A-B)/2`
    B
    `"tan"(A-B)/2`
    C
    `"cot"(A-B)/2`
    D
    none of these

  • If sinA=nsinB , then ((n-1)/(n+1))tan((A+B)/(2))=?

    A
    `sin((A-B)/(2))`
    B
    `tan((A-B)/(2))`
    C
    `cot((A-B)/(2))`
    D
    `tan((A+B)/(2))`

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