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If sin x + cos x = 1/5, then tan 2x is...

If `sin x + cos x = 1/5`, then tan 2x is

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`sinx+cosx=1/5`
we can replace `cosx=sqrt(1-sin^2(x))`
=>`sqrt(1-sin^2(x))=1/5-sinx`
squaring on both sides
`1-sin^(2)x=1/25+sin^(2)x-2/5sinx`
on solving we get
=>`50sin^(2)x-10sinx-24=0`
=>`50sin^(2)x-40sinx+30sinx-24=0`
...
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