The potential energy of a particle in a force field is:
`U = (A)/(r^(2)) - (B)/(r )`,. Where `A` and `B` are positive
constants and `r` is the distance of particle from the centre of the field. For stable equilibrium the distance of the particle is

The potential energy of a particle in a conservative field is U =a/r^3-b/r^2, where a and b are positive constants and r is the distance of particle from the centre of field. For equilibrium, the value of r is

The potential energy of a particle in a conservative field is U =a/r^3 - b/r^2 where a and b are positive constants and r is the distance of particle from the centre of field. For equilibrium, the value of r is

The potential energy of a particle in a force field is : U= A/r^2-B/r^1 , where A and B are positive constant and r is the centre of the field. For stable equilibrium, the distance of the particle is :

The potential energy of a particle in a certain field has the form U=(a//r^2)-(b//r) , where a and b are positive constants and r is the distance from the centre of the field. Find the value of r_0 corresponding to the equilibrium position of the particle, examine whether this position is stable.

The potential energy of a particle in a certain field has the form U=(a//r^2)-(b//r) , where a and b are positive constants and r is the distance from the centre of the field. Find the value of r_0 corresponding to the equilibrium position of the particle, examine whether this position is stable.