The tangents to the curve `y = (x-2)^(2)-1` at its points of intersection with the line `x - y = 3`, intersect at the point:

The tangents to the curve y = (x - 2)^(2) - 1 at its points of intersectio with the line x - y = 3, intersect at the point

The point of intersection of the lines x= 2 and y = 3 is

Equation of the tangent to the curve y=1-2^(x//2) at the point of intersection with the Y-axes is

The equation of the tangents to the curve (1+x^(2))y=1 at the points of its intersection with the curve (x+1)y=1 , is given by

The equation of the tangents to the curve (1+x^(2))y=1 at the points of its intersection with the curve (x+1)y=1 , is given by

The equation of the tangents to the curve (1+x^(2))y=1 at the points of its intersection with the curve (x+1)y=1 , is given by

The equation of the tangents to the curve (1+x^(2))y=1 at the points of its intersection with the curve (x+1)y=1 , is given by

The equation of the tangent to the curve y=1-e^((x)/(2)) at the point of intersection with the y -axis,is