The distance between the ends of wings of an aeroplane is 3m. This aeroplane is descending down with a speed of `300` km/hour. If the horizontal component of earths magnetic field is 0.4 gauss then the value of e.m.f. induced in the wings of the plane will be –

The horizontal component of earth magnetic field is 0.2 gauss and total magnetic field is 0.4 gauss find the angle of dip.

The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. Is

The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. Is

A metre gauge train is running towards north with a speed of 20 m//s . If the vertical component of earth's magnetic induction is 3 xx 10^(-4) Wb//m^(2) , then the e.m.f. induced at the end of the axle is

An aeroplane having a distance of 50 metre between the edges of its wings is flying horizontally with a speed of 360km // hour. If the vertical component of earth’s magnetic field is 4 xx 10^(–4)" weber"//m^(2) , then the induced emf between the edges of its wings will be –

An aeroplane, in which the distance between the tips of thie wings is 50m, is flying horizontally with a speed of 360 km//hour , over a place where the vertical component of earth's magnetic field is 2.0 xx 10^(-4) tesla. The potential difference between the tips of the wings would be

The distance between the edges of the wings of an aeroplane is 30 metre. It is landing down with a velocity of 300 km//hr . If while landing, the wings of the aeroplane be east-west, find out the potentail difference between the edges of the wings. What will happen if the wings are along north south. Take H = 0.4 gauss.

The distance between the extremities of the two wings of an aeroplane is 30m. It is flying horizontally with a velocity of 1080km .h^(-1) . The vertical component of earth's magnetic field in that region is 4.5xx10^(-5)T . Find the emf induced across the extremities of the two wings.