A charged particle projected in a magnetic field
`B=(3hati+4hatj)xx10^-2T`
The acceleration of the particle is found to be
`a=(xhati+2hatj)m/s^2`
find the value of `x`

An experimenter's diary reads as follows, "a charged particle is projected in a magnetic field of (7.0hati-3.0hatj)xx10^(-3)T .The acceleration of the particle is found to be (xhati+7.0hatj)xx10^(-6)m//s^(2) .Find the value of x .

A charged particle moves in a uniform magnetic field B=(2hati-3hatj) T

A charged particle moves in a uniform magnetic field B=(2hati-3hatj) T

Charged particle is projected in a magnetic field of (7hat i-3hat j) times 10^(-3) T . The acceleration of the particle is found to be (xhat i+7hat j) times 10^(-3)m/sec^(2) .The value of x is

A charged particle is inside a magnetic field vecB = (10hati - 6hatj) xx 10^(-4) T . The acceleration of the charged particle is given by veca = 3hati + xhatj m//s^(2) . What should be the value of x for this to be possible?

A charged particle moves in a magnetic field vecB=10hati with initial velocity vecu=5veci+4hatj . The path of the particle will be

A charged particle moves in a magnetic field vecB=10hati with initial velocity vecu=5veci+4hatj . The path of the particle will be

A particle is given an initial velocity of vecu=(3 hati+4 hatj) m//s . Acceleration of the particle is veca=(3t^(2) +2 thatj) m//s^(2) . Find the velocity of particle at t=2s.

A charged particle has acceleration veca=2hati+xhatj in a magnetic field vecB=-3hati+2hatj-4hatk .Find the value of x .