An ellipse has its centre at `(1, -1)` and semi-major axis = 8, which passes through the point `(1, 3)`.If the major axes is parallel to x-axis then the equation of ellipse is

An ellipse has a centre at (1-1), and semimajor axis =8 and which passes through the point (1,3) . If the major axis is parallel to x-axis then the length of its latus rectum then find (t)/(4) .

An ellipse has a centre at (1-1), and semimajor axis =8 and which passes through the point (1,3) . If the major axis is parallel to x-axis then the length of its latus rectum then find (t)/(4) .

An ellipse has its centre (1,-1) and semi major axis is 8 , which passes through the point (1,3) . Then the equation of the ellipse is

If length of the major axis is 8 and e = 1/sqrt(2) Axes are co-ordinate axes then equation of the ellipse is

Find the equation of ellipse,Centre at (0,0) major axis on the y-axis and passes through the points (3,2) and (1,6) .

An ellipse is drawn by taking a diameter of the circle (x-1)^2+y^2=1 as its semi-minor axis and a diameter of the circle x^2+(y-2)^2=4 as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is (1) 4x^2+""y^2=""4 (2) x^2+""4y^2=""8 (3) 4x^2+""y^2=""8 (4) x^2+""4y^2=""16

An ellipse is drawn by taking a diameter of the circle (x-1)^2+y^2=1 as its semi-minor axis and a diameter of the circle x^2+(y-2)^2=4 as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is (1) 4x^2+""y^2=""4 (2) x^2+""4y^2=""8 (3) 4x^2+""y^2=""8 (4) x^2+""4y^2=""16