The binding energy of deuteron `._1^2 H` is `1.112 MeV` per nucleon and an `alpha-`particle `._2^4 He` has a binding energy of `7.047 MeV` per nucleon. Then in the fusion reaction `._1^2H + ._1^2h rarr ._2^4 He + Q`, the energy `Q` released is.

[" The binding energy of deutron "(1H^(2))" is "1.15" MeV per nucleon and an alpha "],[" particle "(2He^(4))" has a binding energy of "7.1" MeV per nucleon.Then in the "],[" reaction "1H^(2)+1H^(2)rarr_(2)He^(4)+Q],[" The energy Q released in MeV is "]

The binding energy per nucleon of ._3^7Li and ._2^4He nuclei are 5.60 MeV and 7.06 MeV respectively. In the nuclear reaction ._3^7Li + ._1^1H to 2._2^4He + Q , the value of energy Q released is

The binding energies per nucleon for a deuteron and an alpha- particle are x_1 and x_2 respectively. What will be the energy Q released in the following reaction ? ._1H^2 + ._1H^2 rarr ._2He^4 + Q .

The binding energies per nucleon for a deuteron and an alpha- particle are x_1 and x_2 respectively. What will be the energy Q released in the following reaction ? ._1H^2 + ._1H^2 rarr ._2He^4 + Q .

The binding energies per nucleon for a deuteron and an alpha- particle are x_1 and x_2 respectively. What will be the energy Q released in the following reaction ? ._1H^2 + ._1H^2 rarr ._2He^4 + Q .

Find the energy Q released in this reaction. 1H^2+1H^2 rarr Q+_2He^4

The binding energies per nucleon for a deuteron and an alpha -particle are x_(1) and x_(2) respectively. What will be the energy Q released in the following reaction? ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(4) + Q

The binding energy per nucleon of "_3^7Li and "_2^4He nuclei are 5.60 MeV and 7.06MeV , respectively . In the nuclear reaction "_3^7Li+ _1^1H rarr _4^2He + _2^4He+Q , the value of energy Q released is:

The binding energies of deutron (._1H^2) and alpha -particle (._2He^4) are 1.25 and 7.2 MeV/nucleon respectively. Which nucleus is more stable?