At `100^(@)"C"`, benzene & toluene have vapour pressure of 1375 & 558 torr respectively. Assuming these two form an ideal binary solution, calculate the composition of the solution that boils at 1 atm & `100^(@)"C"`. What is the composition of vapour issuing at these conditions?

At 90^(@)"C" , the vapour pressure of toluence is 400 torr and tha of sigma-"xylene" is 150 torr. What is the composition of the liquid mixture that boils at 90^(@)"c" , when the pressure is 0.50atm? What is the composition of vapour produced?

The vapour pressure of pure benzene at 88^@C is 957 mm and that of toluene at the same temperature is 379.5 mm. Calculate the composition of benzene toluene mixture boiling at 88^@C at 1 atm pressure

At 90^(@)"C" , the vapour pressure of toluene is 400 torr and tha of sigma-"xylene" is 150 torr. What is the composition of toluene in the liquid mixture that boils at 90^(@)"c" , when the pressure is 0.50atm?

The vapour pressures of benzene and toluene at 293 K are 75 mm and 22 mm Hg respectively. 23.4g of benzene and 64.4 g of toluene are mixed. If the two form and ideal solution, calculate the mole fraction of benzene in the vapour phase assuming that the vapours are in equilibrium with the liquid mixture at this temperature.

At 88^(@)C benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at 88^(@)C at 1 atm pressure? (Consider that benzene toluene form an ideal solution):