A train after travelling 150 km meets with an accident and then proceeds with 3/5 of its former speed and arrives at its destination 8 h late . Had the accident occurred 360 km further , it would have reached the destination 4 h late . What is the total distance travelled by the train ?

A train after travelling 150km meets with an accident and proceeds at (3)/(5) of its former speed and arrives at its destination 8 hours late.Had the accident occurred 360km further,it would have reached the destination 4 hours late.What is the total distance travelled by the train?

A dog after travelling 50 km meets a swami who counsels him to go slower. He then proceeds at 3/4 of his former speed and arrives at his destination 35 minutes late. Had the meeting occurred 24 km further the dog would have reached its destination 25 minutes late. The speed of the dog is

After travelling 200 km a train met with an accident and its speed became 4/5th of its actual speed and reached 45 minutes late. If this accident had happened after 40 more kms the train would have reached the station 30 minutes late. Find out the distance and speed of train.

After travelling a distance of 50 km train meets with an accident and its speed becomes 3/4th of its actual speed and reaches 35 minutes late. If this accident had occurred after travelling 24 km more train would have reached the station 25 minutes late. Find out the distance and speed of train.

After travelling 5 hours a train meets with an accident. Due to this it has to stop 2 hours. After this the train starts moving 55(5)/(9) % of its speed , and reaches to its destination 12(2)/(9) hours late . If the accident had occurred 150 Km ahead on the same line then the train would have reached the destination 10(8)/(9) hours late . Find the original speed of the train ?

A train starts from a station and after traveling 100 km meets with an accident. And then the speed of the train reduces by 1/4th of its former speed. And travelling the remaining distance it reaches to its destination 1(7)/(8) hours late . If the accident occured 60 Km ahead then it reaches 15 min earlier . The find its original speed and the distance of its journey ?

A train moves from a station and after traveling 333 km meets with an accident. And then the speed of the train becomes by 119/787th of its former speed. And tavelling the remaining distance it reaches to its destination 4 hours late. If the accident occured 111 km ahead then it reaches 3 hours late. Then find the distance of its journey?

A train met with an accident 120 km from station A. It completed the remaining journey at 5/6 of its previous speed and reached 2 hours late at station B. Had the accident taken place 300 km further, it would have been only 1 hour late? What is the speed of the train?