`10 xx 10^3. 2.2 xx 10^-6. 10/(0.4)`

10xx10^(3)*2.2xx10^(-6)*(10)/(0.4)

{:("Column A"," ","Column B"),(2 xx 10^1 + 3 xx 10^(0) +4 xx 10^(-1) + 5 xx 10^(-2),,1 xx 10^(-3) + 2 xx 10^(-2) xx 10^(-2) + 3 xx 10^(-1) + 4 xx 10^(0) + 5 xx 10^(1)):}

Solve with due regards to significant figures 4.0 xx (10^-4) - 2.5 xx 10^(-6) .

Solve with due regards to significant figures 4.0 xx (10^-4) - 2.5 xx 10^(-6) .

The rate of a certain reaction at different times is as follows {:("Time",0,10,20,30),("Rate",3.2 xx 10^(-2), 3.18 xx 10^(-2), 3.22 xx 10^(-2), 3.19 xx 10^(-2)):} The order of the reaction is

Write the numeral whose expanded form is given below: ( i ) 6 xx 10^(4)+3 xx 10^(3)+0 xx 10^(2)+7 xx 10^(1)+8 xx 10^(0) ( ii ) 9 xx 10^(6)+7 xx 10^(5)+0 xx 10^(4)+3 xx 10^(3)+2 xx 10^(2)+9 xx 10^(1)+6 xx 10^(0) ( iii ) 8 xx 10^(5)+6 xx 10^(4)+4 xx 10^(3)+2 xx 10^(2)+9 xx 10^(1)+6 xx 10^(0)

Henry 's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.6 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is a. 3.0 xx 10^(-4) b. 4.0 xx 10^(-5) c. 5.0 xx 10^(-4) d. 6.0 xx 10^(-6)

Henry 's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.6 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is a. 3.0 xx 10^(-4) b. 4.0 xx 10^(-5) c. 5.0 xx 10^(-4) d. 6.0 xx 10^(-6)

pH of a saturated solution of Ba(OH)_2 is 12. The value of solubility product K_(sp) " of " Ba(OH)_2 is (a) 3.3 xx 10^(-7) (b) 5.0 xx 10^(-7) (c) 4.0 xx 10^(-6) (d) 5.0 xx 10^(-6)