Find the sum to infinity of the following Geometric Progression: `1,1/3,1/9,...`

Answer

`3/2`

Explanation

Given series is in G.P.

Let `a` = first term and `r` = common ratio

Here, `a=1` and `r=1/3`

`therefore S=a/(1−r)​=1/(1-1/3)​=3/2`.

Thus, the sum of given series is `3/2`.