Home
Class 12
PHYSICS
An alpha-particle of 5MeV energy strikes...

An `alpha`-particle of `5MeV` energy strikes with a nucleus of uranium at stationary at an scattering angle of `108^(@)`. The nearest distance up to which `alpha`particle reaches the nuvles will be of the order of

Promotional Banner

Similar Questions

Explore conceptually related problems

An alpha - particle of 5MeV energy strikes with a nucleus of uranium at stationary at an scattering angle of 180o .The nearest distance up to which alpha - particle reaches the nucleus will be of the order of

What is the impact parameter at which the scattering angle is 10^(@) for Z = 79 and initial energy of the alpha -particle is 5MeV ?

An alpha -particle having energy = 10 meV collides with a nucleus of atomic number 50. The distance of the closest approach is

An alpha -particle of kinetic energy 7.68 MeV is projected towards the nucleus of copper (Z=29). Calculate its distance of nearest approach.

alpha -particles of enegry 400 KeV are boumbardel on nucleus of ._(82)Pb . In scattering of alpha -particles, it minimum distance from nucleus will be