The bisector of two lines L and L are given by `3x^2 - 8xy - 3y^2 + 10x + 20y - 25 = 0`. If the line `L_1` passes through origin, find the equation of line `L_2`.

The equations of bisectors of two lines L_1 & L_2 are 2x-16y-5=0 and 64x+ 8y+35=0 . lf the line L_1 passes through (-11, 4) , the equation of acute angle bisector of L_1 & L_2 is:

The equations of bisectors of two lines L_1 & L_2 are 2x-16y-5=0 and 64x+ 8y+35=0 . lf the line L_1 passes through (-11, 4) , the equation of acute angle bisector of L_1 & L_2 is:

The equations of bisectors of two lines L_1 & L_2 are 2x-16y-5=0 and 64x+ 8y+35=0 . lf the line L_1 passes through (-11, 4) , the equation of acute angle bisector of L_1 & L_2 is:

The equations of bisectors of two lines L_(1)&L_(2) are 2x-16y-5=0 and 64x+8y+35=0. lf the line L_(1) passes through (-11,4), the equation of acute angle bisector of L_(1)o*L_(2) is:

The equation of line l_(1) is y=2x+3 , and the equation of line l_(2) is y=2x-5.

If line l_1 is perpendicular to line l_2 and line l_3 has slope 3 then find the equation of line l_2

If line l_1 is perpendicular to line l_2 and line l_3 has slope 3 then find the equation of line l_1

Consider the lines give by L_1: x+3y -5=0, L_2:3x - ky-1=0, L_3: 5x +2y -12=0