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The solution of the differential equatio...

The solution of the differential equation `(1+y^2)+(x-e^(tan^-1y))dy/dx=0` is (A) `x e^(2 tan^-1y)=e^(tan^-1y)+k` (B) `(x-2)=k e^(-tan^-1y)` (C) ` x e^(tan^-1y)=e^(2 tan^-1y)+k` (D) `x e^(tan^-1y)=tan^-1y+k`

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