A conductance cell when filled with `0.5 M KCI` solution (conductivity `= 6.67 xx 10^(-3) Omega^(-1) cm^(-1)`) register a resistance of `243 Omega`. Its cell constant is .

A conductivity cell when filled with 0.02 M KCl (conductivity = 0.002768 Omega^(-1) cm^(-1) ) has a resistance of 457.3 Omega . What will be the equivalent conductivity of 0.05 N CaCl_(2) solution if the same cell filled with this solution has a resistance of 2020?

Which of the following have maximum molar conductivity. (i) 0.1 M solution and its specific conductivity is 2 xx 10^(-2) Omega^(-1)cm^(-1) ( ii) 0.1M solution and its resistivity is 50 Omega cm.

Conductivity of, a solution is 6.23 xx 10^(-5) Omega^(-1) cm^(-1) and its resistance is 13710 Omega . If the electrode are 0.7 cm apart, calculate the cross-sectional area of electrode.

The specific conductivity of 0.1 N KCl solution is 0.0129 Omega^(-1) cm^(-1) . The resistane of the solution in the cell is 100 Omega . The cell constant of the cell will be

A sample of water from a large swimming pool has a resistance of 9200 Omega at 25^(@)C when placed in a certain conductance cell. When filled with 0.02M KCI solution the cell has a resistance of 85 Omega at 25^(@)C. 500g of NaCI were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 7600 Omega . calculate the volume of water in the pool. Given: Molar conductance of NaCI at that concentration is 126.5 Omega^(-1) cm^(2) mol^(-1) and molar conductivity of KCI at 0.02M is 138 Omega^(-1) cm^(2) mol^(-1) .

A sample of water from a large swimming pool has a resistance of 9200 Omega at 25^(@)C when placed in a certain conductance cell. When filled with 0.02M KCI solution the cell has a resistance of 85 Omega at 25^(@)C. 500g of NaCI were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 7600 Omega . calculate the volume of water in the pool. Given: Molar conductance of NaCI at that concentration is 126.5 Omega^(-1) cm^(2) mol^(-1) and molar conductivity of KCI at 0.02M is 138 Omega^(-1) cm^(2) mol^(-1) .

If specific conductivity of N// 50 KCl solution at 298 K is 0.002765 Omega^(-1) cm^(-1) and resistance of a cell contaning this solution is 100 Omega , calculate the cell constant.