If `sin theta + cos theta =1` then `sin theta cos theta =`

(sin theta + cos theta)^2 = 1 + 2 sin theta cos theta

If sin theta + cos theta =1, the value of sin theta cos theta is

Prove that (cos^(2) theta)/(1-tan theta)+(sin^(3) theta)/(sin theta - cos theta) =1 + sin theta cos theta .

sin theta+cos theta=1 Find (sin theta-cos theta)^(2)

Solve (0^(@) le theta le 360^(@)) : (v) 4 sin theta cos theta = 1 - 2 sin theta + 2cos theta .

(1+ sin theta - cos theta )/( 1+ sin theta + cos theta ) + (1+ sin theta + cos theta )/( 1+ sin theta - cos theta ) =

What is ( sin theta - cos theta + 1 )/( sin theta + cos theta -1) - ( sin theta + 1 )/( cos theta ) equal to ?

(xv) (cos^2 theta) / (1- tan theta) +( sin^3 theta)/ (sin theta - cos theta) = 1 + sin theta cos theta

(1 + sin theta-cos theta) / (1 + sin theta + cos theta) =

Prove that : (1+ sin theta - cos theta) / (1+ sin theta + cos theta ) = tan (theta/2)