Home
Class 11
PHYSICS
A second's pendulum clock havig steeel w...

A second's pendulum clock havig steeel wire is calibrated at `20^(@)`C. When temperature is increased to `30^(@)`C, then calculate how much time does the clock
`[alpha_(Steel)`=`1.2xx10^(-6^(@))C^(-1)`

Promotional Banner

Similar Questions

Explore conceptually related problems

A pendulum clock shows correct time at 0^(@)C . At a higher temperature the clock.

Pendulum clock shows correct time at O^(@)C . At a higher temperature the clock

A steel taps is calibrated at 20^(0)C . When the temperature of the day is -10^(0)C , the percentage error in the measurement with the tap is (alpha = 12 xx 10^(-6 //0)C)

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel = 1.2 xx 10^-5(^@ C)^-1 .

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel = 1.2 xx 10^-5(^@ C)^-1 .

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel) = 1.2 xx 10^(-5).^@C^(-1) .

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel) = 1.2 xx 10^-5(^@C)^-1 .

A pendulum clock has an iron pendulum 1 m long (alpha_("iron")=10^(-5) //^(@)C) . If the temperature rises by 10^(@)C , the clock