`dx/(secx cosec x)`

Evaluate the following : int_(0)^(pi)(x tanx)/(secx "cosec x")dx

int((secx+ "cosec x")(secx- "cosec x"))/(tanx +cotx)dx=

If sinx - cosx = 0, 0^@ltxlt90^@ then the value of (secx +cosec x)^2 is: sinx - cosx = 0, 0^@ltxlt90^@ तो (secx +cosec x)^2 का मान है:

int (dx)/(sec x + "cosec x")

2. int(sec x + cosec x ) dx

int(secx."cosec"x)/(2cotx-secx"cosec x")dx is equal to

int(secx."cosec"x)/(2cotx-secx"cosec x")dx di equal to

int(secx."cosec"x)/(2cotx-secx"cosec x")dx is equal to

int(secx."cosec"x)/(2cotx-secx"cosec x")dx di equal to

int(secx cosec x)/(log(cotx))dx=