On increasing the length by 0.5 mm in a steel wire of length 2 m and area of cross section 2`mm^2`, the force required is [Y for steel `=2.2xx10^11(N)/(m^2)`]

A steel wire of length 2.5 m and area of cross section 1.25 mm^(2) , when it is stretched by a force of 40 N and Y for steel is 2xx10^(11)N//m^(2) . The extension produced in a steel wire is

Determine the force required to double the length of the steel wire of area of cross-section 5 xx 10^(-5) m^(2) . Give Y for steel = 2 xx 10^(11) Nm^(-2) .

Find the energy stored per unit volume of a steel wire of length 1m when it is stretched by 0.2mm. Given Y for steel = 2.1 x 10^11 N/m^2

A steel wire of length 5 m and area of cross-section 4 mm^(2) is stretched by 2 mm by the application of a force. If young's modulus of steel is 2xx10^(11)N//m^(2), then the energy stored in the wire is

A steel wire of length 5 m and area of cross-section 4 mm^(2) is stretched by 2 mm by the application of a force. If young's modulus of steel is 2xx10^(11)N//m^(2), then the energy stored in the wire is

Work done in stretching a wire of length 1 m and of cross-sectional area 1 mm^(2) through 2 mm if Young's modulus of the material of the wire is 2 xx 10 ^(11) N//m^(2) is .......

Calculate the force required to increase the length of a steel wire of cross- sectional area 10^(-6)m^(2) by 0.5% given: Y_(("for steel"))=2xx10^(11)N-m^(2)