Home
Class 11
PHYSICS
A ball projected upwards from the foot o...

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of `6 s` and the ball reaches the ground after `12 s`. The height of the tower is `(g = 10 m//s^2)` :

Promotional Banner

Similar Questions

Explore conceptually related problems

A stone released with zero velocity from the top of a tower, reaches the ground in 4s. The height of the tower is (g = 10 m//s^(2))

A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 m s^(-1) . The ball reaches the ground after 5s. Calculate the height of the tower .

A ball is thrown vertically upwards from the top of a tower with a velocity of 10m/s. If the ball falls on the ground after 5 seconds, the height of the tower will be? (use g=10m/ s^(2) )

A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 "m s"^(-1) . The ball reaches the ground after 5 s. Calculate the height of the tower . Take g= 9.8 "ms"^(-2) ?

A ball is thrown upwards with speed v from the top of a tower and it reaches the ground with speed 3v .The height of the tower is

A ball is thrown upward with speed 10 m/s from the top to the tower reaches the ground with a speed 20 m/s. The height of the tower is [Take g=10m//s^(2) ]

A ball is thrown upward with speed 10 m/s from the top to the tower reaches the ground with a speed 20 m/s. The height of the tower is [Take g=10m//s^(2) ]