In CGS system, the Young's modulusm of a steel wire is `2 xx 10^(12)`. To double the length of a wire of unit cross-section area, the force

A force F doubles the length of wire of cross-section a The Young modulus of wire is

A force F doubles the length of wire of cross-section a The Young modulus of wire is

A 20 N stone is suspended from a wire and its length changes by 1% . If the Young's modulus of the material of wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire will be

Young's modulus of steel is 2xx10^12 cgs unit. Find its value in St unit.

A 20 N stone is suspended from a wire and its length changes by 1% . If the Young's modulus of the material of wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire will be

If young's modulus of steel is 2xx10^(11)N//m^(2) , then the force required to increase the length of a wire of cross section 1 cm^(2) by 1% will be

To determine the Young's modulus of a wire, the formula is Y=(F)/(A)xx(L)/(DeltaL) , where L = length, A = area of cross-section of the wire, DeltaL = change in length of the wire when stretched with a force F. The conversion factor to change it from CGS to MKS system is

For steel Y=2xx10^(11) Nm^(-2) . The force required to double the length of a steel wire of area 1 cm^(2) is

A steel wire 4.0m in length is stretched through 2.0mm .The cross -sectional area of the wire is 2.0 mm^(2) .If young's modulus of steel is 2.0xx10^(11) N//m^(2) (a) the energy density of wire, (b) the elastic potential energy stored in the wire.