Find the equation of line parallel to the y-axis and drawn through the point of intersection of `x \ 7y+\ 5\ =\ 0`and `3x+y \ 7\ =\ 0`.

Explanation

As the line is parallel to the y-axis, the required equation will be,

`x + c = 0->(1)`

Now, we will find the point of intersection of given two lines,

`x-7y+5 = 0 ->(2)`

`3x+y - 7 = 0-> (3)`

Multiplying (3) with 7 and then adding (2) and (3),

`x-7y+5+21x+7y-49 = 0`

`22x = 44=> x = 2`

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