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Evaluate the limits, if existlim(x->3...

Evaluate the limits, if exist`lim_(x->3)(e^x-e^3)/(x-3)`

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The correct Answer is:
`e^3`
`lim_(x->3)(e^x-e^3)/(x-3)`
`=lim_(x->3)(e^x-0)/(1)`
`=e^3`
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